Solution and answer to neutralization problem
A lab technician wants to determine
the molarity of an unknown mono protic acid. What is the
molarity of the solution if 13.61 mL if the acid is
neutralized by 34.69 mL of 0.025 M KOH? The definition for molarity
can be used to produce the following
equation. This means the moles of acid
in a solution are calculated using The moles of base in a
solution are calculated using the terms are defined as
follows Ma is the molarity of the
acid Va is the volume of the
acid Mb is the molarity of the
base Vb is the volume of the
base For a neutral solution at the
end point of a titration the Ma Va = Mb Vb
gather data Ma = unknown = X Mb = 0.025 M KOH Va = 13.61 mL = 0.01361
L Vb = 34.69 mL = 0.03469
L substitute
values X (0.01361 L) = (0.025 M
KOH)(0.03469 L) solve for "x"
X = (0.00086725 M )/(0.01361
) where liters cancel X = 0.06372 M round to 2 sf
because the molarity of the KOH has only "2"
sf. X = 0.064 M
answer
Dr. Walt Volland, All rights reserved 1999-2000